Unit 9: Extraction of Metals
From earthy ores to gleaming metals: exploring the industrial processes that power our world.
9.17 General Principles of Metal Extraction
Most metals are found in the Earth's crust combined with other elements in rocks. An ore is a rock that contains a sufficient concentration of a metal compound to make its extraction economically viable. The process of extraction involves separating the metal from the other elements in its ore, which is primarily a reduction process (gain of electrons) for the metal ion.
The choice of extraction method depends on several factors, mainly:
- Position in the Reactivity Series: The reactivity of a metal determines the stability of its compounds. More reactive metals form more stable compounds and require more powerful, energy-intensive extraction methods.
- Cost of the Process: Economic viability is key. This includes the cost of energy, raw materials (reducing agents), and the equipment required.
- Required Purity of the Metal: Some applications require very pure metals, which may necessitate additional refining steps after the initial extraction.
The main methods are:
- Electrolysis: This is the most powerful method and can extract the most reactive metals. It uses a large amount of electrical energy to decompose the molten metal compound. It is expensive but produces a very pure metal. Used for metals high in the reactivity series (e.g., Aluminum).
- Reduction with Carbon: This is a cheaper method where the metal oxide is heated with carbon (in the form of coke). Carbon acts as a reducing agent, removing oxygen from the metal oxide. This method can only be used for metals that are less reactive than carbon (e.g., Iron, Zinc, Tin, Lead).
Solved Examples:
-
Why can't iron be extracted from its ore using the same method as
aluminum?
Solution: Aluminum is more reactive than iron. Its ore ($Al_2O_3$) is very stable and requires the powerful and energy-intensive method of electrolysis to be broken down. Iron is less reactive, and its ore ($Fe_2O_3$) can be reduced more cheaply using carbon. -
Why is carbon a commonly used reducing agent in metallurgy?
Solution: Carbon (as coke) is used because it is abundant, relatively cheap, and effective at reducing the oxides of many common metals that are less reactive than it, such as iron and zinc.
9.18 Extraction of Aluminium (Electrolysis)
Aluminum is the most abundant metal in the Earth's crust, but it is very reactive. It is extracted from its main ore, bauxite, which is purified to yield aluminum oxide ($Al_2O_3$), also known as alumina.
Alumina has a very high melting point (~2072 °C), making it impractical to electrolyze directly. Instead, it is dissolved in molten cryolite ($Na_3AlF_6$), which acts as a solvent and lowers the operating temperature to a more manageable ~950 °C.
The process, known as the Hall-Héroult process, takes place in a large electrolysis cell with carbon electrodes.
- At the Cathode (Negative Electrode): Aluminum ions gain electrons (are
reduced) and form molten aluminum, which sinks to the bottom of the cell and is tapped
off.
$$ Al^{3+}(l) + 3e^- \rightarrow Al(l) $$ - At the Anode (Positive Electrode): Oxide ions lose electrons (are
oxidized) to form oxygen gas.
$$ 2O^{2-}(l) \rightarrow O_2(g) + 4e^- $$
A significant issue is that the oxygen produced at the high temperature reacts with the
carbon anodes, burning them away to form carbon dioxide.
$$ C(s) + O_2(g) \rightarrow CO_2(g) $$
Because of this, the anodes must be replaced regularly, adding to the cost. The process
consumes vast amounts of electricity, making aluminum production expensive and recycling
very important.
Solved Examples:
-
What is the role of cryolite in the extraction of aluminum?
Solution: Cryolite acts as a solvent for the aluminum oxide ($Al_2O_3$). Its primary purpose is to lower the melting point of the electrolyte from over 2000 °C to around 950 °C, significantly reducing the energy costs of the process. -
Why must the carbon anodes be replaced periodically in the Hall-Héroult
cell?
Solution: The oxygen gas produced at the anode is at a very high temperature. It reacts with the hot carbon anode, oxidizing it to carbon dioxide gas ($C + O_2 \rightarrow CO_2$). This gradually burns the anode away, requiring its regular replacement.
9.19 Extraction of Iron (Blast Furnace)
Iron is extracted from its ore, usually haematite ($Fe_2O_3$), in a giant tower called a blast furnace. The raw materials are iron ore, coke (a source of carbon), and limestone ($CaCO_3$), which are added in layers from the top. A blast of hot air is forced in from the bottom.
Several key reactions occur at different temperatures inside the furnace:
- Production of the Reducing Agent: The coke burns in the hot air to
produce carbon dioxide, which then reacts with more hot coke to form carbon monoxide,
the main reducing agent.
$C(s) + O_2(g) \rightarrow CO_2(g)$
$CO_2(g) + C(s) \rightarrow 2CO(g)$ - Reduction of Iron Ore: The carbon monoxide reduces the iron(III) oxide
to molten iron, which trickles to the bottom of the furnace.
$Fe_2O_3(s) + 3CO(g) \rightarrow 2Fe(l) + 3CO_2(g)$ - Removal of Impurities: The main impurity in the ore is silicon dioxide
($SiO_2$). The limestone decomposes in the heat to form calcium oxide. This basic oxide
reacts with the acidic silicon dioxide to form molten calcium silicate, known as
slag.
$CaCO_3(s) \rightarrow CaO(s) + CO_2(g)$
$CaO(s) + SiO_2(s) \rightarrow CaSiO_3(l)$ (Slag)
The molten slag is less dense than the molten iron, so it floats on top and can be tapped off separately. The molten iron produced, called pig iron, is impure and brittle due to a high carbon content. Most of this is converted to steel in the Basic Oxygen Process, where pure oxygen is blown through the molten iron to oxidize the excess carbon and other impurities.
Solved Examples:
-
What is the main reducing agent in the blast furnace?
Solution: Carbon monoxide (CO). -
What is the purpose of adding limestone to the blast furnace?
Solution: The limestone is added to remove the main impurity, silicon dioxide ($SiO_2$). It decomposes to calcium oxide (CaO), which reacts with the silica to form molten slag ($CaSiO_3$), which can then be separated from the molten iron. -
Why is the iron produced in a blast furnace not immediately useful as a
structural material?
Solution: The "pig iron" from the furnace contains a high percentage of dissolved carbon (around 4%), which makes it very hard but also very brittle. It must be refined into steel to get the desired properties of strength and flexibility.
9.20 Extraction of Tin & Gold
Extraction of Tin
Tin is less reactive than iron and can also be extracted by carbon reduction. Its main ore
is cassiterite ($SnO_2$). The ore is crushed and heated with carbon in a furnace.
$$ SnO_2(s) + 2C(s) \rightarrow Sn(l) + 2CO(g) $$
Extraction of Gold
Gold is extremely unreactive and is found as the native element (not in a compound). However, it is usually found in very low concentrations mixed with large amounts of rock. The extraction process involves separating these tiny flakes from the rock. A common modern method is cyanide leaching.
The crushed ore is treated with a dilute solution of sodium cyanide (NaCN) while air is
bubbled through it. The gold is oxidized and dissolves to form a soluble complex ion.
$$ 4Au(s) + 8NaCN(aq) + O_2(g) + 2H_2O(l) \rightarrow 4Na[Au(CN)_2](aq) + 4NaOH(aq) $$
The gold is then recovered from this solution by reducing it with a more reactive metal,
usually zinc powder.
$$ 2Na[Au(CN)_2](aq) + Zn(s) \rightarrow Na_2[Zn(CN)_4](aq) + 2Au(s) $$
Solved Examples:
-
Why is gold found as a native element, while aluminum is found as an
oxide?
Solution: Gold is at the very bottom of the reactivity series, making it extremely unreactive. It does not readily react with oxygen or other elements. Aluminum is very high in the reactivity series and reacts easily with oxygen to form a very stable oxide. -
What is the role of zinc in the final step of gold extraction?
Solution: Zinc is more reactive than gold. In the final step, it acts as a reducing agent, displacing the gold from the soluble cyanide complex, causing solid gold to precipitate out of the solution. -
Could carbon be used to extract potassium from its ore, KCl?
Solution: No. Potassium is far more reactive than carbon. Carbon is not a strong enough reducing agent to displace potassium from its compounds. A very reactive metal like potassium requires electrolysis for extraction.